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Infrared Spectroscopy, Example #9
Analysis: C6H6S
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From the molecular formula, the compound has "4 degrees of unsaturation" (four double bonds, carbonyls or rings). The large number suggests the presence of an aromatic ring (four degrees of unsaturation).

| 3400-3200 cm-1: | no peak to indicate an OH or NH |
| 3100 cm-1: | sharp peak strongly suggesting unsaturated CH |
| 2900 cm-1: | no peaks to indicate saturated CH |
| 2550 cm-1: | strong peak suggesting an S-H group |
| 2200 cm-1: | no unsymmetrical triple bonds |
| 1710 cm-1: | no carbonyl absorbance |
| 1450-1600 cm-1: | sharp peaks consistent with aromatic carbon-carbon double bonds |
The spectrum seems to be consistent with an aromatic compound containing no saturated C
H and containing a thiol group, an S
H.
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