Using the drawing pallet on the right, draw the structures of the
following compound:
trans-1,3-dibromocyclopentane
The cyclopentane ring is the parent chain; either bromine-bearing
carbon could be carbon #1; the stereochemistry is trans.
Using the drawing pallet on the right, draw the structures of the
following compound:
cis-1-isopropyl-3-methylcyclohexane
The cyclohexane is the parent; the isopropyl group is bonded to carbon
#1 since iso is alphabetically before methyl.
Using the drawing pallet on the right, draw the structures of the
following compound:
(cyclopentylmethyl)cyclopentane
Either cyclopentane ring is the parent; the cyclopentylmethyl group is
simply a substituent.
Using the drawing pallet on the right, draw the structures of the
following compound:
2,2,5-trimethylheptane
The heptane chain is the parent; the lowest number sequence is
generated with the two methyl groups bonded to carbon #2.
Using the drawing pallet on the right, draw the structures of the
following compound:
trans-1-chloro-2-methylcyclopropane
The cyclopropane is the parent; carbon #1 bears the chlorine and the
stereochemistry is trans.
Using the drawing pallet on the right, draw the structures of the
following compound:
trans-1,3-dimethylcyclobutane
The cyclobutane chain is the parent; the two methyl groups are bonded
1-3, relative to each other, and the stereochemistry is E or
trans.
Using the drawing pallet on the right, draw the structures of the
following compound:
hexylcyclooctane
The cyclooctane ring is the parent (8 carbons) with the hexyl residue
bonded to carbon #1.
Using the drawing pallet on the right, draw the structures of the
following compound:
cis-1-methyl-3-nitrocyclopentane
The cyclopentane ring is the parent; the methyl- has higher priority
than the nitro-group alphabetically and the stereochemistry is
cis.
Using the drawing pallet on the right, draw the structures of the
following compound:
trans-1,2-dibromocyclohexane
The cyclohexane is the parent; the two bromines are 1,2 relative to
each other and the stereochemistry is trans.
Using the drawing pallet on the right, draw the structures of the
following compound:
5-bromo-1-cyclobutyl-2-methylpentane
Because the sidechain has a longer hydrocarbon chain than the ring, the pentane is the parent. Substituents on the pentane chain are therefore a cyclobutyl at carbon #1, a methyl at carbon #2 and a bromine at carbon #5. The numbering sequence is selected to give the lowest number sequence at the first point of difference (i.e., 1,2,5 is a lower sequence than 1,4,5).
That is correct!
Sorry, that is not correct. You should modify your structure and try
again. If cis- trans- stereochemistry is required, please make
sure you have drawn the appropriate isomer using "wedge bonds".
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