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The molecular formula for this compound is (C11H16O). Because the number of carbons is odd, the molecular formula and emperical formula are the same.

The compound is a primary alcohol (a primary carbon is bonded to the OH group).

The compound contains one tertiary center, that is, one sp3 carbon which is bonded to three other carbons.

All of the carbons in the benzene ring are sp2 centers.

Does the molecule shown above:

  1. have the empirical formula (C5H6O)? Yes or No
  2. contain a secondary alcohol? Yes or No
  3. contain a tertiary carbon? Yes or No
  4. contain six sp2 centers? Yes or No

Recognizing Structural Features

For the molecule shown on the left, answer each of the questions by clicking on the Yes or No buttons.

When you are done, click on the molecule to view a summary of the answers.